Find the number of terms in the given sequence. 1, 7, 13, ..., 223.
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Find the number of terms in the given sequence. 1, 7, 13, ..., 223.
34
35
36
38
This is an arithmetic progression with a=1, d=6. Last term = a + (n-1)d. 223 = 1 + (n-1)6. 222 = (n-1)6. n-1 = 37. n = 38.
The given sequence is an arithmetic progression with the first term (a) as 1, the common difference (d) as 6, and the last term (L) as 223. Using the formula for the nth term of an arithmetic progression, L = a + (n - 1)d, we substitute the values to get 223 = 1 + (n - 1)6. Solving this equation, 222 equals 6 times (n - 1), which means n - 1 equals 37 and n equals 38. The result is 38.