Multiple choice

The ratio of the ages of a husband and his wife is 9 : 7. The sum of their ages is twice the husband's age five years ago. What was the age of the wife when the husband got married at the age of 33 years?

  1. 25

  2. 22

  3. 23

  4. 28

  5. 21
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

H/W = 9/7 => H=9x, W=7x. Sum = 16x. 16x = 2(H-5) = 2(9x-5) = 18x - 10. 2x = 10, x = 5. H = 45, W = 35. When H was 33, he was 12 years younger. W was 35-12 = 23.

AI explanation

Let the present ages of the husband and wife be 9x and 7x; their sum is 16x, which equals twice the husband's age 5 years ago, giving the equation 16x = 2(9x - 5). Solving this yields 16x = 18x - 10, so x = 5 and their present ages are 45 and 35. The husband got married at 33, which was 12 years ago when the wife was 35 - 12 = 23 years old.

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