Multiple choice

The average age of a family of 4 members, 10 years ago, was 24 years. Two daughters having been born with age difference of 2 years, the present average age of the family remains the same. What is the present age of the younger daughter?

  1. 2 years

  2. 3 years

  3. 3.5 years

  4. 4 years

  5. 4.5 years
Reveal answer Fill a bubble to check yourself
B Correct answer
AI explanation

The average age of the 4 family members 10 years ago was 24, making their total age 96 at that time. Today, the total age of these original 4 members is 96 plus 40, which equals 136. Since the present average age of the 6-member family remains 24, their total present age is 144, meaning the sum of the two daughters' ages is 144 minus 136, or 8 years. Since the daughters have an age difference of 2 years, the younger daughter is (8 - 2) divided by 2, making her 3 years old.

Keep practicing — related questions