Multiple choice

Age of father 10 years ago was three times the age of his son. After 10 years, father's age will be twice that of his son. The ratio of their present ages is

  1. 7 : 3

  2. 9 : 5

  3. 7 : 4

  4. 11 : 7
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let father = F, son = S. (F-10) = 3(S-10) => F-3S = -20. (F+10) = 2(S+10) => F-2S = 10. Subtracting: S = 30. F = 70. Ratio = 70:30 = 7:3.

AI explanation

Let the present ages of father and son be F and S. From the given conditions, F - 10 = 3(S - 10), so F = 3S - 20; and F + 10 = 2(S + 10), so F = 2S + 10. Equating the expressions for F gives 3S - 20 = 2S + 10, which means S = 30, and therefore F = 70. Their ratio is 70 : 30, which simplifies to 7 : 3.

Keep practicing — related questions