What will be the 15th term of the given sequence? 3, 7, 11, 15, 19,...
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What will be the 15th term of the given sequence? 3, 7, 11, 15, 19,...
57
58
59
60
This is an arithmetic progression with a=3 and d=4. The 15th term is a + (15-1)d = 3 + 14*4 = 3 + 56 = 59.
The given sequence is an arithmetic progression with a common difference of 4. To find the 15th term, we use the formula T_n equals a plus open parenthesis n minus 1 close parenthesis times d. Substituting the values gives 3 plus open parenthesis 15 minus 1 close parenthesis times 4, which equals 3 plus 56, making the 15th term 59.