Multiple choice

The ratio of the present ages of Savita and Babita is 9 : 11. If after 10 years, the ratio of their ages becomes 7 : 8, then what is the age of Babita after 10 years?

  1. 32 years

  2. 28 years

  3. 18 years

  4. 22 years

  5. 34 years
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A Correct answer
Explanation

Let ages be 9x and 11x. (9x+10)/(11x+10) = 7/8. 72x + 80 = 77x + 70. 5x = 10, x = 2. Present ages: Savita 18, Babita 22. After 10 years, Babita is 22+10 = 32.

AI explanation

Let the present ages of Savita and Babita be 9x and 11x. After 10 years, the ratio is (9x + 10) / (11x + 10) = 7 / 8; cross-multiplying gives 72x + 80 = 77x + 70, so x = 2. Babita's present age is 11(2) = 22 years, and after 10 years her age will be 32 years.

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