In how many different ways can the letters of the word 'THERAPY' be arranged, so that the vowels never come together?
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In how many different ways can the letters of the word 'THERAPY' be arranged, so that the vowels never come together?
1200
3600
2400
3200
Total arrangements of THERAPY (7 letters, 2 vowels E, A) is 7! = 5040. Treat (EA) as one unit, arrangements = 6! * 2! = 1440. Vowels never together = 5040 - 1440 = 3600.
The word THERAPY has 7 distinct letters with 2 vowels (E and A), so the total number of unrestricted arrangements is 7 factorial. To find the arrangements where the vowels never come together, we first calculate the arrangements where they are together by treating the vowels as a single unit, giving 6 factorial multiplied by 2 factorial for their internal arrangement, which equals 1440. Subtracting the arrangements where vowels are together from the total gives 5040 minus 1440, resulting in 3600.