Multiple choice

What would be the smallest natural number which when divided either by 20 or by 42 or by 76 leaves a remainder of 7 in each case?

  1. 3047

  2. 6047

  3. 7987

  4. 63847
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C Correct answer
Explanation

Find the LCM of 20, 42, 76. LCM(20, 42, 76) = 7980. The number is LCM + remainder = 7980 + 7 = 7987.

AI explanation

Since the number leaves a remainder of 7 in each case, we subtract 7 from the number to make it perfectly divisible by 20, 42, and 76. We find the least common multiple of 20, 42, and 76, which is 7980. Adding the remainder of 7 back to this multiple gives 7987.

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