Multiple choice

The table below gives information about the number of articles manufactured by 5 different branches of a company on 5 days of the week ||||||| |---|---|---|---|---|---|| |Day/Branch|P|Q|R|S|T| |Monday|50|60|70|80|40| |Tuesday|40|50|30|45|60| |Wednesday|20|45|50|40|30| |Thursday|30|65|50|60|30| |Friday|60|30|40|60|40| Which of the following branches has manufactured the maximum number of articles during the 5-day period?

  1. P

  2. Q

  3. R

  4. S

  5. e
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Sum for P: 50+40+20+30+60 = 200. Q: 60+50+45+65+30 = 250. R: 70+30+50+50+40 = 240. S: 80+45+40+60+60 = 285. T: 40+60+30+30+40 = 200. S has the maximum.

AI explanation

We calculate the total number of articles manufactured by each branch during the five days. The totals are as follows: P is 200, Q is 250, R is 240, and S is 285. Branch S manufactured the maximum number of articles, with a total of 285.

Keep practicing — related questions