A train passes two bridges of lengths 500 m and 250 m in 100 seconds and 60 seconds, respectively. Find the length of the train.
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A train passes two bridges of lengths 500 m and 250 m in 100 seconds and 60 seconds, respectively. Find the length of the train.
125 metres
1375 metres
105 metres
150 metres
None of These
Let L be the train length and v be the speed. (L + 500)/100 = v and (L + 250)/60 = v. Equating them: (L + 500)/100 = (L + 250)/60. Simplifying, 6(L + 500) = 10(L + 250), so 6L + 3000 = 10L + 2500. 4L = 500, L = 125.
Let the length of the train be L and its speed be S. Using the distance formula for the first bridge, L plus 500 equals 100S. For the second bridge, L plus 250 equals 60S. Subtracting the second equation from the first gives 250 equals 40S, meaning the speed S is 6.25 m/s. Substituting this speed back into the second equation gives L plus 250 equals 60 times 6.25, so L plus 250 equals 375 and L equals 125. The length of the train is 125 metres.