A thief steals a car at 1:30 p.m. and drives at 40 kmph. At 2:00 p.m, the owner starts chasing his car at 50 kmph. At what time will he catch the thief?

By 2:00 p.m., the thief has a 30 minute head start, creating a gap of 20 kilometers at 40 kmph. The owner travels at a relative speed of 10 kmph, which is the difference between 50 kmph and 40 kmph, to close this gap. Using time equals distance divided by speed, the owner takes 20 divided by 10, or 2 hours, so he catches the thief at 4:00 p.m.

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