A group of 4 men can dig a pit in 15 days. If a man works half as much more as a boy, then 8 men and 6 boys can dig it in
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A group of 4 men can dig a pit in 15 days. If a man works half as much more as a boy, then 8 men and 6 boys can dig it in
6 days
10 days
7 days
5 days
None of these
If a man works 1.5 times as much as a boy, 1 man = 1.5 boys. 4 men = 6 boys. The work takes 15 days. 8 men + 6 boys = 12 boys + 6 boys = 18 boys. Using (M1*D1 = M2*D2), 6 boys * 15 days = 18 boys * D2, so D2 = 90 / 18 = 5 days.
Using the work equivalence method, 4 men complete the work in 15 days, meaning the total work requires 60 man-days. A man works half as much more as a boy, making one man equal to 1.5 boys, so 8 men and 6 boys equal 18 boys. Converting 18 boys back to men gives 12 men, and dividing the total 60 man-days by 12 men yields 5 days.