If a, b, c and d are four numbers such that b is 50% of a, c is 25% less than b, d is 10% more than c, and a is k% more than d, then what is the approximate value of k?

Let a equal 100, which makes b equal 50. Since c is 25 percent less than b, c is 37.5, and since d is 10 percent more than c, d is 41.25. The value of a is 100, which is k percent more than d, so 100 equals 41.25 multiplied by the quantity 1 plus k divided by 100. Solving this equation gives k equals 142.

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