Which of the following is evaluated first:
-
&&
-
||
-
!
-
&&&
In operator precedence, logical NOT (!) has the highest precedence among the given operators. It is evaluated before AND (&&) and OR (||). The order is: ! (highest), then &&, then || (lowest). Option D (&&&) is not a valid operator.
In standard logical-operator precedence (shared across languages like C, Java, and most scripting languages), the unary NOT operator (!) binds tightest and is evaluated before the binary AND (&&), which in turn is evaluated before the binary OR (||). So in an expression mixing these, ! is applied to its operand first, then && combines results, then || combines those. '&&&' isn't a valid operator in these languages, so it can't be 'evaluated first' in any real sense. This precedence ordering (! > && > ||) is a fixed language-design convention, not something context-dependent, making '!' the correct first-evaluated operator.