Which of the following conditional expressions can not be used with an IF-THEN-ELSE-ENDIF construction?

  1. STEP.RC NE 8

  2. ABEND = FALSE

  3. STEP.CC = U4038

  4. STEP.RUN EQ TRUE


Correct Option: C

AI Explanation

To answer this question, we need to understand the syntax and rules of using conditional expressions with an IF-THEN-ELSE-ENDIF construction.

The IF-THEN-ELSE-ENDIF construction is used in programming languages to make decisions based on a condition. It follows the syntax:

IF condition THEN statement(s) ELSE statement(s) ENDIF

The condition in the IF statement is a conditional expression that evaluates to either true or false.

Let's go through each option to understand why it can or cannot be used with an IF-THEN-ELSE-ENDIF construction:

A. STEP.RC NE 8 - This option can be used with an IF-THEN-ELSE-ENDIF construction because it is a valid conditional expression. It checks if the value of the STEP.RC variable is not equal to 8.

B. ABEND = FALSE - This option can be used with an IF-THEN-ELSE-ENDIF construction because it is a valid conditional expression. It checks if the value of the ABEND variable is equal to false.

C. STEP.CC = U4038 - This option cannot be used with an IF-THEN-ELSE-ENDIF construction because it is missing the comparison operator. The correct syntax for this condition would be STEP.CC EQ U4038. Therefore, this option is incorrect.

D. STEP.RUN EQ TRUE - This option can be used with an IF-THEN-ELSE-ENDIF construction because it is a valid conditional expression. It checks if the value of the STEP.RUN variable is equal to true.

The correct answer is C. STEP.CC = U4038. This option is incorrect because it is missing the comparison operator.

Therefore, the conditional expression that cannot be used with an IF-THEN-ELSE-ENDIF construction is C. STEP.CC = U4038.

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