Multiple choice technology programming languages

In the previous question, what are the maximum possibilities?

  1. 0 and 9

  2. 0

  3. 3 and 4 and 5

  4. 9
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A Correct answer
Explanation

In the previous number trick, the deleted digit can only be 0 or 9 because both have the same remainder (0) when divided by 9. After subtracting the digit sum, the result is divisible by 9. When three remaining digits sum to a multiple of 9, the missing digit must complete that divisibility, and only 0 and 9 share this property.

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