main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }

Keep practicing — related questions

• 1)main() { int i = 5; printf(“%d %d %d %d %d”,i++,i--,++i,--i,i); }
• void main() { int i=5; i+=i*=i-=i/i; printf("%d",i); }
• 1)main() { printf(“%x”,-1<<4); }
• The following program prints main() { int i = 5; i = (++i) / (i ++); printf(“%d”,i); }
• int main() { int a=500,b=100,c=30,d=40,e=19; a+=b-=c*=d/=e%=5; printf("%d %d %d %d %d",a,b,c,d,e); }
• The output of the following program will be main() { int a = 1, b=2, c=3; printf(“%d”, a+=(a+=3,5,a)); }
• main(){ int a,b; a=0; b=(a=1)?2:3; printf("%d %d",a,b); }
• 1)main() { int i = 0; for( ; i++ ; printf(“%d”,i)); printf(“%d”,i); }