Multiple choice technology programming languages

Which of the following options is true for the following program: try { if (choice) { while (true) } else { system .exit(1): } }finally { codetocleanup(); }

  1. Runtime Exception

  2. finally block will be executed

  3. finally block will not be executed

  4. Compilation error in else block
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

System.exit() terminates the JVM immediately, preventing the finally block from executing. Additionally, the while(true) loop in the if branch never exits, so the finally block would never be reached in that case either. Only if neither branch executes would finally run, but the structure guarantees one of them does.

AI explanation

'Finally block will not be executed' is correct, in both possible paths through the code. If choice is true, the code enters an infinite while(true) loop with no break, so control never reaches the end of the try block and the finally clause is never reached at all — the thread simply loops forever. If choice is false, System.exit(1) is called, which immediately terminates the JVM; unlike a normal return or exception, System.exit() does not run pending finally blocks during shutdown. So regardless of which branch is taken, codetocleanup() in finally never executes. (Note the snippet as given has minor typos — lowercase 'system.exit' and a colon instead of a semicolon, and the while loop appears to be missing a body statement — but the underlying behavior being tested, infinite loop vs. System.exit both bypassing finally, is the intended concept.)

Keep practicing — related questions