Multiple choice technology programming languages my $val = ‘x’; print ref($val); scalar any decimal value empty value x Reveal answer Fill a bubble to check yourself C Correct answer Explanation The ref() function returns the type of a reference (HASH, ARRAY, etc.). For a plain scalar like 'x' (which is not a reference), ref() returns an empty string (false value). It doesn't return 'scalar' - that's a data type, not a reference type.