Multiple choice technology web technology

What is output to the web page on the second access to the same instance of the following JSP? (Choose one.) <%@ page language="java" %> Chapter 6 Question 2

Chapter 6 Question 2

<%! int x = 0; %> <%! public void jspInit() { System.out.println(x++); } %> <%= x++ %> <% System.out.println(x); %> <% jspInit(); %>

  1. 0

  2. 1

  3. 2

  4. 3

  5. 4

  6. Page does not translate.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

On first access: x=0 (declaration), jspInit() prints 0 then increments x to 1, expression prints 1 then increments to 2, scriptlet prints 2, manual jspInit() prints 2 then increments to 3. Output to page: 1. On second access: x is now 3 (persistent), jspInit() prints 3 then increments to 4, expression prints 4 then increments to 5, scriptlet prints 5, manual jspInit() prints 5 then increments to 6. Output to page: 4. Wait, let me reconsider. The <%! int x = 0; %> is a class-level field, initialized once when the JSP servlet loads. On first page hit: x starts at 0. Expression <%= x++ %> prints 0, x becomes 1. Scriptlet prints 1. jspInit() prints x (1), increments to 2. Output: 0. On second hit: x is 2. Expression prints 2, x becomes 3. Scriptlet prints 3. jspInit() prints 3, increments to 4. Output: 3. Hmm, answer D says 3. But wait, let me trace more carefully. The <%! int x = 0; %> initializes x to 0 once. jspInit() is called by the container when the servlet is initialized, but here it's also called manually. The key is that x persists between requests. If output is 3 on second access, then first access must have output something that left x at 3. Let me trace: First access: x=0. Expression prints 0, x=1. Scriptlet prints 1. jspInit() prints 1, x=2. Page output: 0. Second access: x=2. Expression prints 2, x=3. Scriptlet prints 3. jspInit() prints 3, x=4. Page output: 2. That doesn't match. Let me reconsider.

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