Multiple choice technology programming languages

Given: 1. class Ring { 2. final static int x2 = 7; 3. final static Integer x4 = 8; 4. public static void main(String[] args) { 5. Integer x1 = 5; 6. String s = "a"; 7. if(xl < 9) s += "b"; 8. switch(x1) { 9. case 5: s += "c"; 10. case x2: s += "d"; 11. case x4: s += "e"; 12. } 13. System.out.println(s); 14. } 15. } What is the result?

  1. abc

  2. abcde

  3. Compilation fails due only to an error on line 7.

  4. Compilation fails due only to an error on line 8.

  5. Compilation fails due only to an error on line 10.

  6. Compilation fails due only to an error on line 11.

Reveal answer Fill a bubble to check yourself
F Correct answer
Explanation

The code has multiple errors. Line 7 has 'xl' (lowercase L) instead of 'x1', which would cause a compilation error. However, the more critical error for this question is on line 11: 'case x4' attempts to use a variable (x4) in a switch case statement. In Java, switch case expressions must be constant expressions (compile-time constants). While x4 is declared final, it's of type Integer (wrapper class), not int, so it's not a compile-time constant. Cases can only use: constant int values, final int primitives initialized with literals, or enum constants. Integer wrapper objects are never compile-time constants.