What happens in a method if an exception is thrown in a try{} block and there is NO MATCHING catch{} block?
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This is not legal, so the program will not compile.
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The method throws the exception to its caller if there were no matching catch{} block.
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The program halts immediately.
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The program ignores the exception.
When an exception is thrown in a try block and no matching catch block exists, the exception propagates up the call stack. The method throws the exception to its caller, following Java's exception propagation mechanism. This allows higher-level methods to handle the exception or continue propagating it. The program does not halt immediately, ignore the exception, or fail to compile - this is legal Java code.
When a try block throws an exception that has no matching catch in the current method, the exception propagates up the call stack to the calling method, which then gets a chance to handle it (or propagate it further). This is standard exception propagation — the program doesn't halt immediately nor silently ignore the exception at that point, and the lack of a matching catch doesn't cause a compile error.