Two lines 3x-5y=10 and 2x-10y=-3 were given and the point of intersection of these lines lies in which quadrant?

This is a coordinate geometry problem requiring finding intersection point location. Solving the system: 3x - 5y = 10 and 2x - 10y = -3. From the second equation: x = 5y - 1.5. Substituting into first: 3(5y - 1.5) - 5y = 10, giving 15y - 4.5 - 5y = 10, so 10y = 14.5, and y = 1.45. Then x = 5(1.45) - 1.5 = 7.25 - 1.5 = 5.75. The intersection point (5.75, 1.45) has both coordinates positive, placing it in the first quadrant.