A bag contains 3 red, 4 black and 2 white balls. What is the probability of drawing a red and a white ball in two successive draws, each ball being put back after it is drawn?

Total balls = 3+4+2 = 9. First draw (red): P(Red) = 3/9 = 1/3. Ball is replaced, so still 9 balls. Second draw (white): P(White) = 2/9. P(Red then White) = (1/3) × (2/9) = 2/27. But the question asks for red AND white in any order. P(White then Red) = (2/9) × (1/3) = 2/27. Total = 2/27 + 2/27 = 4/27. Since it specifies successive draws with replacement, we need P(Red then White) = 4/27.