Simply the boolean function f=A.B.C.D + A.C.D + A.D
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A.D
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B.C
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A.B+C
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NONE OF THESE
To simplify f = A.B.C.D + A.C.D + A.D, factor out A.D from all terms: f = A.D(B.C + C + 1). Since C + 1 = 1, and B.C + C = C(B + 1) = C, the expression reduces to A.D. This is a direct application of Boolean algebra factorization and identity laws.
To simplify the given Boolean function f = A.B.C.D + A.C.D + A.D, let's apply Boolean algebra and simplify each term:
f = A.B.C.D + A.C.D + A.D
First, let's factor out the common term 'A.D' from each term:
f = A.D(B.C + C + 1)
Now, let's simplify the expression (B.C + C + 1):
B.C + C + 1 = C(B + 1) + 1 = C + 1
Substituting this back into the original expression:
f = A.D(C + 1)
Now, we can see that the simplified form of the Boolean function f is A.D.
Therefore, the correct answer is A) A.D.