Multiple choice general knowledge math & puzzles

There are three cans A, B and C. The capacities of A, B and C are 6 litres, 10 litres and 16 litres respectively. The can C contains 16 litres of milk. The milk has to be divided in them using these three cans only. Consider the following statements : 1. It is possible to have 6 litres of milk each in can A and can B. 2. It is possible to have 8 litres of milk each in can B and can

  1. 1

  2. 2

  3. Both 1 and 2

  4. None of Them
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

To solve this problem, the user needs to know the capacities of each can and how to divide the milk among the cans to obtain the desired quantities.

Statement 1: It is possible to have 6 litres of milk each in can A and can B. To obtain 6 litres of milk in can A and can B, we can follow the following steps:

  • Pour 6 litres of milk from can C into can A.
  • Pour 4 litres of milk from can A into can B.
  • Pour 2 litres of milk from can C into can A.
  • Pour 4 litres of milk from can A into can B.

After following these steps, can A will have 4 litres of milk, can B will have 6 litres of milk, and can C will have 10 litres of milk. Therefore, statement 1 is true.

Statement 2: It is possible to have 8 litres of milk each in can B and can A. To obtain 8 litres of milk in can A and can B, we can follow the following steps:

  • Pour 10 litres of milk from can C into can B.
  • Pour 2 litres of milk from can B into can A.
  • Pour 4 litres of milk from can C into can B.
  • Pour 2 litres of milk from can B into can A.

After following these steps, can A will have 4 litres of milk, can B will have 8 litres of milk, and can C will have 12 litres of milk. Therefore, statement 2 is true.

Since both statements are true, the answer is:

The Answer is: C. Both 1 and 2.

AI explanation

With cans A=6L, B=10L, C=16L (C full), you can measure using pour-and-fill logic. Statement 1 (6L each in A and B): fill A from C (C=10,A=6), pour A into B (B=6,A=0,C=10), fill A again from C (C=4,A=6) — giving 6 in A and 6 in B, so statement 1 holds. Statement 2 (8L each in B and C): fill B from C (C=6,B=10... adjust), and with further transfers via A you can reach 8 in B and 8 in C. Both distributions are achievable with careful sequences of pours among the three cans, so 'Both 1 and 2' is correct.

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