Multiple choice general knowledge

A game-show host has placed a car behind one of three doors. There is a goat behind each of the other doors. "First you point toward a door," he says. "Then I'll open one of the other doors to reveal a goat. After I've shown you the goat, you make your final choice whether to stick with your initial choice of doors, or to switch to the remaining door. You win whatever is behind the door." You begin by pointing to door number 1. The host shows you that door number 3 has a goat. What should you do (assuming you want the best odds of winning the car)?

  1. Switch to door #2

  2. Stay with door #1

  3. It doesn't matter

  4. Punch the host in the jaw
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

This is the classic Monty Hall problem. When you pick door 1 initially, you have a 1/3 chance the car is behind it and a 2/3 chance it's behind doors 2 or 3 combined. When the host (who knows where the car is) reveals door 3 has a goat, that entire 2/3 probability collapses onto door 2. Staying gives 1/3 odds; switching gives 2/3 odds. You should switch.

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