Multiple choice general knowledge math & puzzles

John is 7 times as old as his son. 10 years hence he will be 3 times as old as his son. What are their present ages (in years)?

  1. 4,28

  2. 5,35

  3. 3,21

  4. 7,49
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's age = s, John's age = 7s. After 10 years: 7s + 10 = 3(s + 10) → 7s + 10 = 3s + 30 → 4s = 20 → s = 5. John = 7 × 5 = 35 years. Present ages: 5 and 35.

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