Multiple choice general knowledge math & puzzles

From a pack of cards Jack, Queen, King & ace are removed. Then the algebraic sum of rest of the cards is

  1. 201

  2. 210

  3. 216

  4. 236
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A standard deck has 4 suits. Removing Jack (11), Queen (12), King (13), and Ace (1) leaves cards 2 through 10. The sum of cards 2 to 10 in one suit is 54. For 4 suits, the total sum is $54 \times 4 = 216$.

AI explanation

To find the algebraic sum of the rest of the cards after removing Jack, Queen, King, and Ace, we need to consider the numerical values assigned to each card.

In a standard deck of cards, Jack, Queen, and King are assigned the values of 11, 12, and 13 respectively. Ace is assigned the value of 1.

The remaining cards in the deck are the number cards from 2 to 10. These cards have numerical values equivalent to their face value.

So, the algebraic sum of the rest of the cards can be calculated as:

2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 54

Therefore, the correct answer is C) 216.

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